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33103121441213 is a prime number
BaseRepresentation
bin1111000011011011010111…
…10010110110000110111101
311100012121221110011000112202
413201231223302312012331
513314330143042104323
6154223210345041245
76654423131420435
oct741555362660675
9140177843130482
1033103121441213
11a602a5606990a
123867734486225
1315617c3373005
148262b1abd2c5
153c614c7d8d28
hex1e1b6bcb61bd

33103121441213 has 2 divisors, whose sum is σ = 33103121441214. Its totient is φ = 33103121441212.

The previous prime is 33103121441209. The next prime is 33103121441249. The reversal of 33103121441213 is 31214412130133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23034259557604 + 10068861883609 = 4799402^2 + 3173147^2 .

It is a cyclic number.

It is not a de Polignac number, because 33103121441213 - 22 = 33103121441209 is a prime.

It is a super-2 number, since 2×331031214412132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33103121441413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16551560720606 + 16551560720607.

It is an arithmetic number, because the mean of its divisors is an integer number (16551560720607).

Almost surely, 233103121441213 is an apocalyptic number.

It is an amenable number.

33103121441213 is a deficient number, since it is larger than the sum of its proper divisors (1).

33103121441213 is an equidigital number, since it uses as much as digits as its factorization.

33103121441213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 33103121441213 its reverse (31214412130133), we get a palindrome (64317533571346).

The spelling of 33103121441213 in words is "thirty-three trillion, one hundred three billion, one hundred twenty-one million, four hundred forty-one thousand, two hundred thirteen".