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33104031413 is a prime number
BaseRepresentation
bin11110110101001001…
…110110111010110101
310011110002002000222112
4132311021312322311
51020244113001123
623112514140405
72251230424055
oct366511667265
9104402060875
1033104031413
11130483a9852
1264ba581705
1331774a208b
1418607b1565
15cdb3bbd78
hex7b5276eb5

33104031413 has 2 divisors, whose sum is σ = 33104031414. Its totient is φ = 33104031412.

The previous prime is 33104031403. The next prime is 33104031419. The reversal of 33104031413 is 31413040133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22880192644 + 10223838769 = 151262^2 + 101113^2 .

It is an emirp because it is prime and its reverse (31413040133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 33104031413 - 28 = 33104031157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (33104031419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16552015706 + 16552015707.

It is an arithmetic number, because the mean of its divisors is an integer number (16552015707).

Almost surely, 233104031413 is an apocalyptic number.

It is an amenable number.

33104031413 is a deficient number, since it is larger than the sum of its proper divisors (1).

33104031413 is an equidigital number, since it uses as much as digits as its factorization.

33104031413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 33104031413 its reverse (31413040133), we get a palindrome (64517071546).

The spelling of 33104031413 in words is "thirty-three billion, one hundred four million, thirty-one thousand, four hundred thirteen".