Base | Representation |
---|---|
bin | 110000001011101000001… |
… | …110110001000101101001 |
3 | 102201112022202011021021201 |
4 | 300023220032301011221 |
5 | 413221432334044423 |
6 | 11013021223004201 |
7 | 461133121110025 |
oct | 60135016610551 |
9 | 12645282137251 |
10 | 3311021003113 |
11 | 106721804680a |
12 | 455846299661 |
13 | 1b02c6a2b015 |
14 | b637ba15385 |
15 | 5b1d97402ad |
hex | 302e83b1169 |
3311021003113 has 2 divisors, whose sum is σ = 3311021003114. Its totient is φ = 3311021003112.
The previous prime is 3311021003111. The next prime is 3311021003149. The reversal of 3311021003113 is 3113001201133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2584866493504 + 726154509609 = 1607752^2 + 852147^2 .
It is a cyclic number.
It is not a de Polignac number, because 3311021003113 - 21 = 3311021003111 is a prime.
Together with 3311021003111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3311021003111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655510501556 + 1655510501557.
It is an arithmetic number, because the mean of its divisors is an integer number (1655510501557).
Almost surely, 23311021003113 is an apocalyptic number.
It is an amenable number.
3311021003113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3311021003113 is an equidigital number, since it uses as much as digits as its factorization.
3311021003113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 3311021003113 its reverse (3113001201133), we get a palindrome (6424022204246).
The spelling of 3311021003113 in words is "three trillion, three hundred eleven billion, twenty-one million, three thousand, one hundred thirteen".
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