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3311103101213 is a prime number
BaseRepresentation
bin110000001011101101000…
…111111100100100011101
3102201112112110122021201002
4300023231013330210131
5413222114343214323
611013033314400045
7461135135662055
oct60135507744435
912645473567632
103311103101213
11106725a420286
12455869890025
131b030aa4438b
14b63888a6565
155b1e1a5a828
hex302ed1fc91d

3311103101213 has 2 divisors, whose sum is σ = 3311103101214. Its totient is φ = 3311103101212.

The previous prime is 3311103101197. The next prime is 3311103101227. The reversal of 3311103101213 is 3121013011133.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2118197892409 + 1192905208804 = 1455403^2 + 1092202^2 .

It is an emirp because it is prime and its reverse (3121013011133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3311103101213 - 24 = 3311103101197 is a prime.

It is a super-2 number, since 2×33111031012132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3311103101113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655551550606 + 1655551550607.

It is an arithmetic number, because the mean of its divisors is an integer number (1655551550607).

Almost surely, 23311103101213 is an apocalyptic number.

It is an amenable number.

3311103101213 is a deficient number, since it is larger than the sum of its proper divisors (1).

3311103101213 is an equidigital number, since it uses as much as digits as its factorization.

3311103101213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 3311103101213 its reverse (3121013011133), we get a palindrome (6432116112346).

The spelling of 3311103101213 in words is "three trillion, three hundred eleven billion, one hundred three million, one hundred one thousand, two hundred thirteen".