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3311140002013 is a prime number
BaseRepresentation
bin110000001011101111010…
…100101101100011011101
3102201112122001002001002101
4300023233110231203131
5413222203320031023
611013041113325101
7461136064431424
oct60135724554335
912645561061071
103311140002013
111067279234408
1245587a106791
131b031559437c
14b638d7502bb
155b1e4de91ad
hex302ef52d8dd

3311140002013 has 2 divisors, whose sum is σ = 3311140002014. Its totient is φ = 3311140002012.

The previous prime is 3311140001989. The next prime is 3311140002043. The reversal of 3311140002013 is 3102000411133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2407779096804 + 903360905209 = 1551702^2 + 950453^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3311140002013 is a prime.

It is a super-2 number, since 2×33111400020132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3311140002043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655570001006 + 1655570001007.

It is an arithmetic number, because the mean of its divisors is an integer number (1655570001007).

Almost surely, 23311140002013 is an apocalyptic number.

It is an amenable number.

3311140002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

3311140002013 is an equidigital number, since it uses as much as digits as its factorization.

3311140002013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 3311140002013 its reverse (3102000411133), we get a palindrome (6413140413146).

The spelling of 3311140002013 in words is "three trillion, three hundred eleven billion, one hundred forty million, two thousand, thirteen".