Base | Representation |
---|---|
bin | 100101101001001110001111… |
… | …0111101110101110111001011 |
3 | 1121102101212020102120222200121 |
4 | 1023102130132331311313023 |
5 | 321400041323420304003 |
6 | 3132122521553244111 |
7 | 126513463430232112 |
oct | 11322343675656713 |
9 | 1542355212528617 |
10 | 331121023213003 |
11 | 96561701329671 |
12 | 31179580863637 |
13 | 1129b769ca0b2a |
14 | 5baa4b3402c79 |
15 | 284333eabdcbd |
hex | 12d271ef75dcb |
331121023213003 has 2 divisors, whose sum is σ = 331121023213004. Its totient is φ = 331121023213002.
The previous prime is 331121023212997. The next prime is 331121023213021. The reversal of 331121023213003 is 300312320121133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 331121023213003 - 29 = 331121023212491 is a prime.
It is a super-2 number, since 2×3311210232130032 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (331121023213073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165560511606501 + 165560511606502.
It is an arithmetic number, because the mean of its divisors is an integer number (165560511606502).
Almost surely, 2331121023213003 is an apocalyptic number.
331121023213003 is a deficient number, since it is larger than the sum of its proper divisors (1).
331121023213003 is an equidigital number, since it uses as much as digits as its factorization.
331121023213003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 331121023213003 its reverse (300312320121133), we get a palindrome (631433343334136).
The spelling of 331121023213003 in words is "three hundred thirty-one trillion, one hundred twenty-one billion, twenty-three million, two hundred thirteen thousand, three".
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