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3311300120230 = 25331130012023
BaseRepresentation
bin110000001011111000110…
…111100000111010100110
3102201120001012100212222201
4300023320313200322212
5413223020312321410
611013105033245114
7461143050422404
oct60137067407246
912646035325881
103311300120230
111067350657613
1245590386379a
131b033c7c688b
14b63a6b10474
155b203ec683a
hex302f8de0ea6

3311300120230 has 8 divisors (see below), whose sum is σ = 5960340216432. Its totient is φ = 1324520048088.

The previous prime is 3311300120159. The next prime is 3311300120257. The reversal of 3311300120230 is 320210031133.

3311300120230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 3311300120198 and 3311300120207.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165565006002 + ... + 165565006021.

It is an arithmetic number, because the mean of its divisors is an integer number (745042527054).

Almost surely, 23311300120230 is an apocalyptic number.

3311300120230 is a deficient number, since it is larger than the sum of its proper divisors (2649040096202).

3311300120230 is a wasteful number, since it uses less digits than its factorization.

3311300120230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 331130012030.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 3311300120230 its reverse (320210031133), we get a palindrome (3631510151363).

The spelling of 3311300120230 in words is "three trillion, three hundred eleven billion, three hundred million, one hundred twenty thousand, two hundred thirty".

Divisors: 1 2 5 10 331130012023 662260024046 1655650060115 3311300120230