Base | Representation |
---|---|
bin | 1111000011101101111101… |
… | …00100100001101100111101 |
3 | 11100020120200212210222201220 |
4 | 13201312332210201230331 |
5 | 13320011112113144013 |
6 | 154231540451023553 |
7 | 6655225330036041 |
oct | 741667644415475 |
9 | 140216625728656 |
10 | 33113100131133 |
11 | a607206849290 |
12 | 386965a29abb9 |
13 | 156272380b969 |
14 | 82697b096021 |
15 | 3c6533887b23 |
hex | 1e1dbe921b3d |
33113100131133 has 32 divisors (see below), whose sum is σ = 48238962573312. Its totient is φ = 20037526924800.
The previous prime is 33113100131119. The next prime is 33113100131149.
33113100131133 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 33113100131133 - 225 = 33113066576701 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (33113100135133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 494583166 + ... + 494650112.
It is an arithmetic number, because the mean of its divisors is an integer number (1507467580416).
Almost surely, 233113100131133 is an apocalyptic number.
33113100131133 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
33113100131133 is a deficient number, since it is larger than the sum of its proper divisors (15125862442179).
33113100131133 is a wasteful number, since it uses less digits than its factorization.
33113100131133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89905.
The product of its (nonzero) digits is 729, while the sum is 24.
It can be divided in two parts, 33113100 and 131133, that added together give a palindrome (33244233).
The spelling of 33113100131133 in words is "thirty-three trillion, one hundred thirteen billion, one hundred million, one hundred thirty-one thousand, one hundred thirty-three".
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