Base | Representation |
---|---|
bin | 100101101001010100110000… |
… | …0110001000010000010010111 |
3 | 1121102110012100100001200210222 |
4 | 1023102221200301002002113 |
5 | 321400304001041200033 |
6 | 3132133154030504555 |
7 | 126514500201350444 |
oct | 11322514061020227 |
9 | 1542405310050728 |
10 | 331135012053143 |
11 | 9656762a6a5281 |
12 | 3118022566515b |
13 | 1129cb891a322c |
14 | 5bab03d2129cb |
15 | 28438acc4a598 |
hex | 12d2a60c42097 |
331135012053143 has 2 divisors, whose sum is σ = 331135012053144. Its totient is φ = 331135012053142.
The previous prime is 331135012053119. The next prime is 331135012053169. The reversal of 331135012053143 is 341350210531133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 331135012053143 - 212 = 331135012049047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331135012053103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165567506026571 + 165567506026572.
It is an arithmetic number, because the mean of its divisors is an integer number (165567506026572).
Almost surely, 2331135012053143 is an apocalyptic number.
331135012053143 is a deficient number, since it is larger than the sum of its proper divisors (1).
331135012053143 is an equidigital number, since it uses as much as digits as its factorization.
331135012053143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48600, while the sum is 35.
Adding to 331135012053143 its reverse (341350210531133), we get a palindrome (672485222584276).
The spelling of 331135012053143 in words is "three hundred thirty-one trillion, one hundred thirty-five billion, twelve million, fifty-three thousand, one hundred forty-three".
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