3311400050051 has 2 divisors, whose sum is σ = 3311400050052. Its totient is φ = 3311400050050.

The previous prime is 3311400049999. The next prime is 3311400050053. The reversal of 3311400050051 is 1500500041133.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3311400050051 is a prime.

Together with 3311400050053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3311400049999 and 3311400050026.

It is not a weakly prime, because it can be changed into another prime (3311400050053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1655700025025 + 1655700025026.

It is an arithmetic number, because the mean of its divisors is an integer number (1655700025026).

Almost surely, 2^{3311400050051} is an apocalyptic number.

3311400050051 is a deficient number, since it is larger than the sum of its proper divisors (1).

3311400050051 is an equidigital number, since it uses as much as digits as its factorization.

3311400050051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 3311400050051 its reverse (1500500041133), we get a palindrome (4811900091184).

The spelling of 3311400050051 in words is "three trillion, three hundred eleven billion, four hundred million, fifty thousand, fifty-one".