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33114122141133 = 3111462968593769
BaseRepresentation
bin1111000011101111110110…
…11111001011110111001101
311100020200100002220110220010
413201313323133023313031
513320020210232004013
6154232230120143433
76655262550010035
oct741677337136715
9140220302813803
1033114122141133
11a607690735550
1238698a4607b79
1315628574840c7
14826a36ad28c5
153c65934657c3
hex1e1dfb7cbdcd

33114122141133 has 16 divisors (see below), whose sum is σ = 48169289044800. Its totient is φ = 20067792766080.

The previous prime is 33114122141131. The next prime is 33114122141159.

It is a happy number.

33114122141133 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 33114122141133 - 21 = 33114122141131 is a prime.

It is a super-3 number, since 3×331141221411333 (a number of 42 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 33114122141133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (33114122141131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33814128 + ... + 34779641.

It is an arithmetic number, because the mean of its divisors is an integer number (3010580565300).

Almost surely, 233114122141133 is an apocalyptic number.

33114122141133 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

It is an amenable number.

33114122141133 is a deficient number, since it is larger than the sum of its proper divisors (15055166903667).

33114122141133 is a wasteful number, since it uses less digits than its factorization.

33114122141133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68608412.

The product of its digits is 5184, while the sum is 30.

It can be divided in two parts, 3311412 and 2141133, that added together give a palindrome (5452545).

The spelling of 33114122141133 in words is "thirty-three trillion, one hundred fourteen billion, one hundred twenty-two million, one hundred forty-one thousand, one hundred thirty-three".

Divisors: 1 3 11 33 14629 43887 160919 482757 68593769 205781307 754531459 2263594377 1003458246701 3010374740103 11038040713711 33114122141133