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331143334133413 is a prime number
BaseRepresentation
bin100101101001011000101000…
…0110011001111111010100101
31121102110222211022112011210011
41023102301100303033322211
5321400423022014232123
63132141051513530221
7126515213343022234
oct11322612063177245
91542428738464704
10331143334133413
119657011025836a
1231181968713971
13112a08b4375399
145bab5cc59ab1b
152843be8666e0d
hex12d2c50ccfea5

331143334133413 has 2 divisors, whose sum is σ = 331143334133414. Its totient is φ = 331143334133412.

The previous prime is 331143334133399. The next prime is 331143334133473. The reversal of 331143334133413 is 314331433341133.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 310714760172609 + 20428573960804 = 17627103^2 + 4519798^2 .

It is a cyclic number.

It is not a de Polignac number, because 331143334133413 - 221 = 331143332036261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (331143334133473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165571667066706 + 165571667066707.

It is an arithmetic number, because the mean of its divisors is an integer number (165571667066707).

Almost surely, 2331143334133413 is an apocalyptic number.

It is an amenable number.

331143334133413 is a deficient number, since it is larger than the sum of its proper divisors (1).

331143334133413 is an equidigital number, since it uses as much as digits as its factorization.

331143334133413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 419904, while the sum is 40.

Adding to 331143334133413 its reverse (314331433341133), we get a palindrome (645474767474546).

The spelling of 331143334133413 in words is "three hundred thirty-one trillion, one hundred forty-three billion, three hundred thirty-four million, one hundred thirty-three thousand, four hundred thirteen".