Base | Representation |
---|---|
bin | 100101101001110011011111… |
… | …1110011010101000000101111 |
3 | 1121102200111202022100200120222 |
4 | 1023103212333303111000233 |
5 | 321402344202414000421 |
6 | 3132223353030001555 |
7 | 126522325205215466 |
oct | 11323467763250057 |
9 | 1542614668320528 |
10 | 331201031000111 |
11 | 96592628674278 |
12 | 31190b8b1a62bb |
13 | 112a617a9011ac |
14 | 5bb03032079dd |
15 | 2845473ac9cab |
hex | 12d39bfcd502f |
331201031000111 has 2 divisors, whose sum is σ = 331201031000112. Its totient is φ = 331201031000110.
The previous prime is 331201031000083. The next prime is 331201031000249. The reversal of 331201031000111 is 111000130102133.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331201031000111 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 331201031000111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331201036000111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165600515500055 + 165600515500056.
It is an arithmetic number, because the mean of its divisors is an integer number (165600515500056).
Almost surely, 2331201031000111 is an apocalyptic number.
331201031000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
331201031000111 is an equidigital number, since it uses as much as digits as its factorization.
331201031000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 331201031000111 its reverse (111000130102133), we get a palindrome (442201161102244).
The spelling of 331201031000111 in words is "three hundred thirty-one trillion, two hundred one billion, thirty-one million, one hundred eleven", and thus it is an aban number.
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