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331210220130214 = 2165605110065107
BaseRepresentation
bin100101101001110111110001…
…1100001000100111110100110
31121102201101110201022212022221
41023103233203201010332212
5321403022012323131324
63132231512524542554
7126523102005432325
oct11323574341047646
91542641421285287
10331210220130214
11965965136a3777
12311929146b1a5a
13112a6cb3600c99
145bb09357b20bc
1528458106b50e4
hex12d3be3844fa6

331210220130214 has 4 divisors (see below), whose sum is σ = 496815330195324. Its totient is φ = 165605110065106.

The previous prime is 331210220130193. The next prime is 331210220130227. The reversal of 331210220130214 is 412031022012133.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×3312102201302142 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82802555032552 + ... + 82802555032555.

It is an arithmetic number, because the mean of its divisors is an integer number (124203832548831).

Almost surely, 2331210220130214 is an apocalyptic number.

331210220130214 is a deficient number, since it is larger than the sum of its proper divisors (165605110065110).

331210220130214 is a wasteful number, since it uses less digits than its factorization.

331210220130214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 165605110065109.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 331210220130214 its reverse (412031022012133), we get a palindrome (743241242142347).

The spelling of 331210220130214 in words is "three hundred thirty-one trillion, two hundred ten billion, two hundred twenty million, one hundred thirty thousand, two hundred fourteen".

Divisors: 1 2 165605110065107 331210220130214