Base | Representation |
---|---|
bin | 110000001100101001001… |
… | …001011000110110000101 |
3 | 102201122010122111201222211 |
4 | 300030221021120312011 |
5 | 413231200142042013 |
6 | 11013321250223421 |
7 | 461202114303004 |
oct | 60145111306605 |
9 | 12648118451884 |
10 | 3312110112133 |
11 | 10677268a2509 |
12 | 455aaab84b71 |
13 | 1b043b567724 |
14 | b644251ac3b |
15 | 5b25017423d |
hex | 30329258d85 |
3312110112133 has 2 divisors, whose sum is σ = 3312110112134. Its totient is φ = 3312110112132.
The previous prime is 3312110112089. The next prime is 3312110112191.
3312110112133 is nontrivially palindromic in base 10.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1659052193764 + 1653057918369 = 1288042^2 + 1285713^2 .
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 3312110112133 - 221 = 3312108014981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3312110122133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656055056066 + 1656055056067.
It is an arithmetic number, because the mean of its divisors is an integer number (1656055056067).
Almost surely, 23312110112133 is an apocalyptic number.
It is an amenable number.
3312110112133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3312110112133 is an equidigital number, since it uses as much as digits as its factorization.
3312110112133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
It can be divided in two parts, 3312110 and 112133, that added together give a palindrome (3424243).
The spelling of 3312110112133 in words is "three trillion, three hundred twelve billion, one hundred ten million, one hundred twelve thousand, one hundred thirty-three".
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