Base | Representation |
---|---|
bin | 110000001100101001111… |
… | …011000011100001001111 |
3 | 102201122011120000012212111 |
4 | 300030221323003201033 |
5 | 413231212010210413 |
6 | 11013322433244451 |
7 | 461202333050521 |
oct | 60145173034117 |
9 | 12648146005774 |
10 | 3312123131983 |
11 | 1067733185516 |
12 | 455ab3403727 |
13 | 1b0441175993 |
14 | b6444149a11 |
15 | 5b251396d3d |
hex | 30329ec384f |
3312123131983 has 2 divisors, whose sum is σ = 3312123131984. Its totient is φ = 3312123131982.
The previous prime is 3312123131963. The next prime is 3312123132163. The reversal of 3312123131983 is 3891313212133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3312123131983 - 217 = 3312123000911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3312123131923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656061565991 + 1656061565992.
It is an arithmetic number, because the mean of its divisors is an integer number (1656061565992).
Almost surely, 23312123131983 is an apocalyptic number.
3312123131983 is a deficient number, since it is larger than the sum of its proper divisors (1).
3312123131983 is an equidigital number, since it uses as much as digits as its factorization.
3312123131983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69984, while the sum is 40.
The spelling of 3312123131983 in words is "three trillion, three hundred twelve billion, one hundred twenty-three million, one hundred thirty-one thousand, nine hundred eighty-three".
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