Base | Representation |
---|---|
bin | 100101101001111001001000… |
… | …1100011011111110111110001 |
3 | 1121102201200000012120122000021 |
4 | 1023103302101203133313301 |
5 | 321403044002320001431 |
6 | 3132233114351523441 |
7 | 126523234242061042 |
oct | 11323622143376761 |
9 | 1542650005518007 |
10 | 331213140000241 |
11 | 965977819042a4 |
12 | 311933aa529581 |
13 | 112a735a50ac25 |
14 | 5bb0b314ba8c9 |
15 | 2845931bcbb11 |
hex | 12d3c918dfdf1 |
331213140000241 has 64 divisors (see below), whose sum is σ = 354581660160000. Its totient is φ = 308784179773440.
The previous prime is 331213140000233. The next prime is 331213140000247. The reversal of 331213140000241 is 142000041312133.
It is a cyclic number.
It is not a de Polignac number, because 331213140000241 - 23 = 331213140000233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (331213140000247) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 157795682610 + ... + 157795684708.
It is an arithmetic number, because the mean of its divisors is an integer number (5540338440000).
Almost surely, 2331213140000241 is an apocalyptic number.
It is an amenable number.
331213140000241 is a deficient number, since it is larger than the sum of its proper divisors (23368520159759).
331213140000241 is a wasteful number, since it uses less digits than its factorization.
331213140000241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4282.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 331213140000241 its reverse (142000041312133), we get a palindrome (473213181312374).
The spelling of 331213140000241 in words is "three hundred thirty-one trillion, two hundred thirteen billion, one hundred forty million, two hundred forty-one", and thus it is an aban number.
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