Base | Representation |
---|---|
bin | 100101101001111001001000… |
… | …1100011011111110111110111 |
3 | 1121102201200000012120122000111 |
4 | 1023103302101203133313313 |
5 | 321403044002320001442 |
6 | 3132233114351523451 |
7 | 126523234242061051 |
oct | 11323622143376767 |
9 | 1542650005518014 |
10 | 331213140000247 |
11 | 965977819042aa |
12 | 311933aa529587 |
13 | 112a735a50ac2b |
14 | 5bb0b314ba8d1 |
15 | 2845931bcbb17 |
hex | 12d3c918dfdf7 |
331213140000247 has 2 divisors, whose sum is σ = 331213140000248. Its totient is φ = 331213140000246.
The previous prime is 331213140000233. The next prime is 331213140000269. The reversal of 331213140000247 is 742000041312133.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331213140000247 is a prime.
It is a super-2 number, since 2×3312131400002472 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331213140000287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165606570000123 + 165606570000124.
It is an arithmetic number, because the mean of its divisors is an integer number (165606570000124).
Almost surely, 2331213140000247 is an apocalyptic number.
331213140000247 is a deficient number, since it is larger than the sum of its proper divisors (1).
331213140000247 is an equidigital number, since it uses as much as digits as its factorization.
331213140000247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
The spelling of 331213140000247 in words is "three hundred thirty-one trillion, two hundred thirteen billion, one hundred forty million, two hundred forty-seven", and thus it is an aban number.
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