Base | Representation |
---|---|
bin | 100101101001111001100010… |
… | …0110100001000110100110111 |
3 | 1121102201202020010211011022201 |
4 | 1023103303010310020310313 |
5 | 321403102233000002221 |
6 | 3132233335552405331 |
7 | 126523264454001631 |
oct | 11323630464106467 |
9 | 1542652203734281 |
10 | 331214000000311 |
11 | 965980832a605a |
12 | 311935aa546847 |
13 | 112a746673aacc |
14 | 5bb0bb37c3a51 |
15 | 2845982456891 |
hex | 12d3cc4d08d37 |
331214000000311 has 2 divisors, whose sum is σ = 331214000000312. Its totient is φ = 331214000000310.
The previous prime is 331214000000209. The next prime is 331214000000423. The reversal of 331214000000311 is 113000000412133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 331214000000311 - 217 = 331213999869239 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (331214000004311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165607000000155 + 165607000000156.
It is an arithmetic number, because the mean of its divisors is an integer number (165607000000156).
Almost surely, 2331214000000311 is an apocalyptic number.
331214000000311 is a deficient number, since it is larger than the sum of its proper divisors (1).
331214000000311 is an equidigital number, since it uses as much as digits as its factorization.
331214000000311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 331214000000311 its reverse (113000000412133), we get a palindrome (444214000412444).
The spelling of 331214000000311 in words is "three hundred thirty-one trillion, two hundred fourteen billion, three hundred eleven", and thus it is an aban number.
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