Base | Representation |
---|---|
bin | 100101101001111100011001… |
… | …0010100010100011100000011 |
3 | 1121102202100001111111010120201 |
4 | 1023103320302110110130003 |
5 | 321403202312310322243 |
6 | 3132240232245150031 |
7 | 126523602434110555 |
oct | 11323706224243403 |
9 | 1542670044433521 |
10 | 331220132120323 |
11 | 9659a73a766636 |
12 | 311948200bb317 |
13 | 112a7c02cb52a4 |
14 | 5bb11d5d854d5 |
15 | 2845be098b04d |
hex | 12d3e32514703 |
331220132120323 has 2 divisors, whose sum is σ = 331220132120324. Its totient is φ = 331220132120322.
The previous prime is 331220132120291. The next prime is 331220132120347. The reversal of 331220132120323 is 323021231022133.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 331220132120323 - 25 = 331220132120291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 331220132120291 and 331220132120300.
It is not a weakly prime, because it can be changed into another prime (331220132120023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165610066060161 + 165610066060162.
It is an arithmetic number, because the mean of its divisors is an integer number (165610066060162).
Almost surely, 2331220132120323 is an apocalyptic number.
331220132120323 is a deficient number, since it is larger than the sum of its proper divisors (1).
331220132120323 is an equidigital number, since it uses as much as digits as its factorization.
331220132120323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 331220132120323 its reverse (323021231022133), we get a palindrome (654241363142456).
The spelling of 331220132120323 in words is "three hundred thirty-one trillion, two hundred twenty billion, one hundred thirty-two million, one hundred twenty thousand, three hundred twenty-three".
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