Base | Representation |
---|---|
bin | 1001101000111101101… |
… | …10100011101010110011 |
3 | 1011122221222212111021221 |
4 | 10310132312203222303 |
5 | 20411324401201042 |
6 | 412055350325511 |
7 | 32634122253112 |
oct | 4643666435263 |
9 | 1148858774257 |
10 | 331230100147 |
11 | 118523835821 |
12 | 54240359897 |
13 | 25308cc68cb |
14 | 12062ab3c79 |
15 | 89392bbd67 |
hex | 4d1eda3ab3 |
331230100147 has 2 divisors, whose sum is σ = 331230100148. Its totient is φ = 331230100146.
The previous prime is 331230100073. The next prime is 331230100181. The reversal of 331230100147 is 741001032133.
It is a strong prime.
It is an emirp because it is prime and its reverse (741001032133) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331230100147 is a prime.
It is not a weakly prime, because it can be changed into another prime (331230107147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165615050073 + 165615050074.
It is an arithmetic number, because the mean of its divisors is an integer number (165615050074).
Almost surely, 2331230100147 is an apocalyptic number.
331230100147 is a deficient number, since it is larger than the sum of its proper divisors (1).
331230100147 is an equidigital number, since it uses as much as digits as its factorization.
331230100147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
The spelling of 331230100147 in words is "three hundred thirty-one billion, two hundred thirty million, one hundred thousand, one hundred forty-seven".
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