Base | Representation |
---|---|
bin | 110000001101011110010… |
… | …100001000001101001101 |
3 | 102201201102210222102202201 |
4 | 300031132110020031031 |
5 | 413240012020320023 |
6 | 11013545553121501 |
7 | 461233165244035 |
oct | 60153624101515 |
9 | 12651383872681 |
10 | 3313002120013 |
11 | 1068044366203 |
12 | 4560b9859291 |
13 | 1b05512c3441 |
14 | b64c8b968c5 |
15 | 5b2a3622bad |
hex | 3035e50834d |
3313002120013 has 2 divisors, whose sum is σ = 3313002120014. Its totient is φ = 3313002120012.
The previous prime is 3313002119983. The next prime is 3313002120059. The reversal of 3313002120013 is 3100212003133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3312993346569 + 8773444 = 1820163^2 + 2962^2 .
It is a cyclic number.
It is not a de Polignac number, because 3313002120013 - 25 = 3313002119981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3313002120083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1656501060006 + 1656501060007.
It is an arithmetic number, because the mean of its divisors is an integer number (1656501060007).
Almost surely, 23313002120013 is an apocalyptic number.
It is an amenable number.
3313002120013 is a deficient number, since it is larger than the sum of its proper divisors (1).
3313002120013 is an equidigital number, since it uses as much as digits as its factorization.
3313002120013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 3313002120013 its reverse (3100212003133), we get a palindrome (6413214123146).
The spelling of 3313002120013 in words is "three trillion, three hundred thirteen billion, two million, one hundred twenty thousand, thirteen".
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