Base | Representation |
---|---|
bin | 1111000100001101101010… |
… | …01110011011011000010111 |
3 | 11100022012122020202010001222 |
4 | 13202012311032123120113 |
5 | 13320300443020243221 |
6 | 154243433554440555 |
7 | 6656400223611236 |
oct | 742066516333027 |
9 | 140265566663058 |
10 | 33130123212311 |
11 | a613451942114 |
12 | 3870a0b29315b |
13 | 1564207523a68 |
14 | 827713c62b1d |
15 | 3c6bcd0bd9ab |
hex | 1e21b539b617 |
33130123212311 has 2 divisors, whose sum is σ = 33130123212312. Its totient is φ = 33130123212310.
The previous prime is 33130123212301. The next prime is 33130123212317. The reversal of 33130123212311 is 11321232103133.
It is a strong prime.
It is an emirp because it is prime and its reverse (11321232103133) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33130123212311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33130123212317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16565061606155 + 16565061606156.
It is an arithmetic number, because the mean of its divisors is an integer number (16565061606156).
Almost surely, 233130123212311 is an apocalyptic number.
33130123212311 is a deficient number, since it is larger than the sum of its proper divisors (1).
33130123212311 is an equidigital number, since it uses as much as digits as its factorization.
33130123212311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 33130123212311 its reverse (11321232103133), we get a palindrome (44451355315444).
The spelling of 33130123212311 in words is "thirty-three trillion, one hundred thirty billion, one hundred twenty-three million, two hundred twelve thousand, three hundred eleven".
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