Base | Representation |
---|---|
bin | 110000001101100100011… |
… | …101100010101110110101 |
3 | 102201201201000001001020021 |
4 | 300031210131202232311 |
5 | 413240214421020003 |
6 | 11014004115405141 |
7 | 461235556660150 |
oct | 60154435425665 |
9 | 12651630031207 |
10 | 3313105251253 |
11 | 10680975a6236 |
12 | 4561282b37b1 |
13 | 1b0569792245 |
14 | b64d8760c97 |
15 | 5b2ac6e52bd |
hex | 30364762bb5 |
3313105251253 has 64 divisors (see below), whose sum is σ = 3988832698368. Its totient is φ = 2692941431040.
The previous prime is 3313105251251. The next prime is 3313105251263. The reversal of 3313105251253 is 3521525013133.
3313105251253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3313105251253 - 21 = 3313105251251 is a prime.
It is a super-3 number, since 3×33131052512533 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3313105251251) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1095964500 + ... + 1095967522.
It is an arithmetic number, because the mean of its divisors is an integer number (62325510912).
Almost surely, 23313105251253 is an apocalyptic number.
It is an amenable number.
3313105251253 is a deficient number, since it is larger than the sum of its proper divisors (675727447115).
3313105251253 is a wasteful number, since it uses less digits than its factorization.
3313105251253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3802.
The product of its (nonzero) digits is 40500, while the sum is 34.
The spelling of 3313105251253 in words is "three trillion, three hundred thirteen billion, one hundred five million, two hundred fifty-one thousand, two hundred fifty-three".
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