Base | Representation |
---|---|
bin | 1001101001000111010… |
… | …11101010011011011011 |
3 | 1011200011122100020210212 |
4 | 10310203223222123123 |
5 | 20412011122132311 |
6 | 412111403201335 |
7 | 32636125066526 |
oct | 4644353523333 |
9 | 1150148306725 |
10 | 331311130331 |
11 | 11856554aa15 |
12 | 5426351624b |
13 | 2531ca27b6c |
14 | 1206d767bbd |
15 | 8941475c8b |
hex | 4d23aea6db |
331311130331 has 2 divisors, whose sum is σ = 331311130332. Its totient is φ = 331311130330.
The previous prime is 331311130307. The next prime is 331311130351. The reversal of 331311130331 is 133031113133.
It is a strong prime.
It is an emirp because it is prime and its reverse (133031113133) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-331311130331 is a prime.
It is a super-2 number, since 2×3313111303312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 331311130297 and 331311130306.
It is not a weakly prime, because it can be changed into another prime (331311130351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165655565165 + 165655565166.
It is an arithmetic number, because the mean of its divisors is an integer number (165655565166).
Almost surely, 2331311130331 is an apocalyptic number.
331311130331 is a deficient number, since it is larger than the sum of its proper divisors (1).
331311130331 is an equidigital number, since it uses as much as digits as its factorization.
331311130331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729, while the sum is 23.
Adding to 331311130331 its reverse (133031113133), we get a palindrome (464342243464).
The spelling of 331311130331 in words is "three hundred thirty-one billion, three hundred eleven million, one hundred thirty thousand, three hundred thirty-one".
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