Base | Representation |
---|---|
bin | 100101101010110001000101… |
… | …1101101101101111001011001 |
3 | 1121110011011011102212221222221 |
4 | 1023111202023231231321121 |
5 | 321412031100040200441 |
6 | 3132404230041144041 |
7 | 126535020035423305 |
oct | 11325421355557131 |
9 | 1543134142787887 |
10 | 331333301100121 |
11 | 966337336a2111 |
12 | 311b274418b021 |
13 | 112b5799bac568 |
14 | 5bb688dd9ad05 |
15 | 2848b15da58d1 |
hex | 12d588bb6de59 |
331333301100121 has 2 divisors, whose sum is σ = 331333301100122. Its totient is φ = 331333301100120.
The previous prime is 331333301100089. The next prime is 331333301100127. The reversal of 331333301100121 is 121001103333133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 309585432601600 + 21747868498521 = 17595040^2 + 4663461^2 .
It is a cyclic number.
It is not a de Polignac number, because 331333301100121 - 25 = 331333301100089 is a prime.
It is not a weakly prime, because it can be changed into another prime (331333301100127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165666650550060 + 165666650550061.
It is an arithmetic number, because the mean of its divisors is an integer number (165666650550061).
Almost surely, 2331333301100121 is an apocalyptic number.
It is an amenable number.
331333301100121 is a deficient number, since it is larger than the sum of its proper divisors (1).
331333301100121 is an equidigital number, since it uses as much as digits as its factorization.
331333301100121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 331333301100121 its reverse (121001103333133), we get a palindrome (452334404433254).
The spelling of 331333301100121 in words is "three hundred thirty-one trillion, three hundred thirty-three billion, three hundred one million, one hundred thousand, one hundred twenty-one".
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