Base | Representation |
---|---|
bin | 11110110110111100… |
… | …100100110111110011 |
3 | 10011112011122212212221 |
4 | 132312330210313303 |
5 | 1020324312312201 |
6 | 23115510501511 |
7 | 2252044144306 |
oct | 366674446763 |
9 | 104464585787 |
10 | 33134104051 |
11 | 13063379874 |
12 | 6508664897 |
13 | 31807a1139 |
14 | 186479cb3d |
15 | cddd5c4a1 |
hex | 7b6f24df3 |
33134104051 has 2 divisors, whose sum is σ = 33134104052. Its totient is φ = 33134104050.
The previous prime is 33134104001. The next prime is 33134104057. The reversal of 33134104051 is 15040143133.
It is a strong prime.
It is an emirp because it is prime and its reverse (15040143133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33134104051 - 29 = 33134103539 is a prime.
It is a super-2 number, since 2×331341040512 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (33134104057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16567052025 + 16567052026.
It is an arithmetic number, because the mean of its divisors is an integer number (16567052026).
Almost surely, 233134104051 is an apocalyptic number.
33134104051 is a deficient number, since it is larger than the sum of its proper divisors (1).
33134104051 is an equidigital number, since it uses as much as digits as its factorization.
33134104051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 33134104051 its reverse (15040143133), we get a palindrome (48174247184).
The spelling of 33134104051 in words is "thirty-three billion, one hundred thirty-four million, one hundred four thousand, fifty-one".
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