Base | Representation |
---|---|
bin | 11110110111010100… |
… | …011010000001001011 |
3 | 10011112121102021011022 |
4 | 132313110122001023 |
5 | 1020332412213201 |
6 | 23120252423055 |
7 | 2252151223163 |
oct | 366724320113 |
9 | 104477367138 |
10 | 33140351051 |
11 | 13066956285 |
12 | 650a777a8b |
13 | 3181b7a6a2 |
14 | 18655475a3 |
15 | cde69341b |
hex | 7b751a04b |
33140351051 has 2 divisors, whose sum is σ = 33140351052. Its totient is φ = 33140351050.
The previous prime is 33140350993. The next prime is 33140351053. The reversal of 33140351051 is 15015304133.
It is a strong prime.
It is an emirp because it is prime and its reverse (15015304133) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33140351051 is a prime.
Together with 33140351053, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 33140351051.
It is not a weakly prime, because it can be changed into another prime (33140351053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16570175525 + 16570175526.
It is an arithmetic number, because the mean of its divisors is an integer number (16570175526).
Almost surely, 233140351051 is an apocalyptic number.
33140351051 is a deficient number, since it is larger than the sum of its proper divisors (1).
33140351051 is an equidigital number, since it uses as much as digits as its factorization.
33140351051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 33140351051 its reverse (15015304133), we get a palindrome (48155655184).
The spelling of 33140351051 in words is "thirty-three billion, one hundred forty million, three hundred fifty-one thousand, fifty-one".
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