331412110344142 has 4 divisors (see below), whose sum is σ = 497118165516216. Its totient is φ = 165706055172070.

The previous prime is 331412110344127. The next prime is 331412110344143. The reversal of 331412110344142 is 241443011214133.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×331412110344142³ (a number of 45 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 331412110344098 and 331412110344107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (331412110344143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82853027586034 + ... + 82853027586037.

It is an arithmetic number, because the mean of its divisors is an integer number (124279541379054).

Almost surely, 2^{331412110344142} is an apocalyptic number.

331412110344142 is a deficient number, since it is larger than the sum of its proper divisors (165706055172074).

331412110344142 is a wasteful number, since it uses less digits than its factorization.

331412110344142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165706055172073.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 331412110344142 its reverse (241443011214133), we get a palindrome (572855121558275).

The spelling of 331412110344142 in words is "three hundred thirty-one trillion, four hundred twelve billion, one hundred ten million, three hundred forty-four thousand, one hundred forty-two".