Base | Representation |
---|---|
bin | 1001101001010011100… |
… | …00111000110000101011 |
3 | 1011200102202100001101111 |
4 | 10310221300320300223 |
5 | 20412213232204201 |
6 | 412125450131151 |
7 | 32641504256155 |
oct | 4645160706053 |
9 | 1150382301344 |
10 | 331413163051 |
11 | 1186080aa683 |
12 | 54291720ab7 |
13 | 25337c00959 |
14 | 1207d127ad5 |
15 | 894a3ccb51 |
hex | 4d29c38c2b |
331413163051 has 2 divisors, whose sum is σ = 331413163052. Its totient is φ = 331413163050.
The previous prime is 331413163049. The next prime is 331413163087. The reversal of 331413163051 is 150361314133.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 331413163051 - 21 = 331413163049 is a prime.
Together with 331413163049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (331413163001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165706581525 + 165706581526.
It is an arithmetic number, because the mean of its divisors is an integer number (165706581526).
Almost surely, 2331413163051 is an apocalyptic number.
331413163051 is a deficient number, since it is larger than the sum of its proper divisors (1).
331413163051 is an equidigital number, since it uses as much as digits as its factorization.
331413163051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 331413163051 its reverse (150361314133), we get a palindrome (481774477184).
The spelling of 331413163051 in words is "three hundred thirty-one billion, four hundred thirteen million, one hundred sixty-three thousand, fifty-one".
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