Base | Representation |
---|---|
bin | 1100010110001001… |
… | …1010110100111101 |
3 | 22112222010110122001 |
4 | 3011202122310331 |
5 | 23241404244313 |
6 | 1304505222301 |
7 | 145061451136 |
oct | 30542326475 |
9 | 8488113561 |
10 | 3314134333 |
11 | 14508191a4 |
12 | 785a91991 |
13 | 40a7c0943 |
14 | 236218c8d |
15 | 145e45add |
hex | c589ad3d |
3314134333 has 2 divisors, whose sum is σ = 3314134334. Its totient is φ = 3314134332.
The previous prime is 3314134321. The next prime is 3314134339. The reversal of 3314134333 is 3334314133.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2016189604 + 1297944729 = 44902^2 + 36027^2 .
It is a cyclic number.
It is not a de Polignac number, because 3314134333 - 213 = 3314126141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3314134339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657067166 + 1657067167.
It is an arithmetic number, because the mean of its divisors is an integer number (1657067167).
Almost surely, 23314134333 is an apocalyptic number.
It is an amenable number.
3314134333 is a deficient number, since it is larger than the sum of its proper divisors (1).
3314134333 is an equidigital number, since it uses as much as digits as its factorization.
3314134333 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11664, while the sum is 28.
The square root of 3314134333 is about 57568.5185930644. The cubic root of 3314134333 is about 1490.9281086148.
Adding to 3314134333 its reverse (3334314133), we get a palindrome (6648448466).
The spelling of 3314134333 in words is "three billion, three hundred fourteen million, one hundred thirty-four thousand, three hundred thirty-three".
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