3314393941 has 2 divisors, whose sum is σ = 3314393942. Its totient is φ = 3314393940.

The previous prime is 3314393921. The next prime is 3314393959. The reversal of 3314393941 is 1493934133.

3314393941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2309186916 + 1005207025 = 48054^2 + 31705^2 .

It is an emirp because it is prime and its reverse (1493934133) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3314393941 - 2¹³ = 3314385749 is a prime.

It is a super-3 number, since 3×3314393941³ (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 3314393894 and 3314393903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3314393921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657196970 + 1657196971.

It is an arithmetic number, because the mean of its divisors is an integer number (1657196971).

Almost surely, 2^3314393941 is an apocalyptic number.

It is an amenable number.

3314393941 is a deficient number, since it is larger than the sum of its proper divisors (1).

3314393941 is an equidigital number, since it uses as much as digits as its factorization.

3314393941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 104976, while the sum is 40.

The square root of 3314393941 is about 57570.7733229284. The cubic root of 3314393941 is about 1490.9670375094.

The spelling of 3314393941 in words is "three billion, three hundred fourteen million, three hundred ninety-three thousand, nine hundred forty-one".