Base | Representation |
---|---|
bin | 110000001110110100110… |
… | …000101000101000010111 |
3 | 102201212011212222222202111 |
4 | 300032310300220220113 |
5 | 413300444310332211 |
6 | 11014345522251451 |
7 | 461314135561036 |
oct | 60166460505027 |
9 | 12655155888674 |
10 | 3314452433431 |
11 | 1068718a9a137 |
12 | 4564434b6b87 |
13 | 1b0722909b69 |
14 | b65c564471d |
15 | 5b33ab05421 |
hex | 303b4c28a17 |
3314452433431 has 2 divisors, whose sum is σ = 3314452433432. Its totient is φ = 3314452433430.
The previous prime is 3314452433399. The next prime is 3314452433437. The reversal of 3314452433431 is 1343342544133.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3314452433431 - 25 = 3314452433399 is a prime.
It is a super-2 number, since 2×33144524334312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3314452433437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1657226216715 + 1657226216716.
It is an arithmetic number, because the mean of its divisors is an integer number (1657226216716).
Almost surely, 23314452433431 is an apocalyptic number.
3314452433431 is a deficient number, since it is larger than the sum of its proper divisors (1).
3314452433431 is an equidigital number, since it uses as much as digits as its factorization.
3314452433431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 622080, while the sum is 40.
Adding to 3314452433431 its reverse (1343342544133), we get a palindrome (4657794977564).
The spelling of 3314452433431 in words is "three trillion, three hundred fourteen billion, four hundred fifty-two million, four hundred thirty-three thousand, four hundred thirty-one".
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