Base | Representation |
---|---|
bin | 11110110111100111… |
… | …110101101011100101 |
3 | 10011112222000001212112 |
4 | 132313213311223211 |
5 | 1020340213220333 |
6 | 23120553530405 |
7 | 2252242430465 |
oct | 366747655345 |
9 | 104488001775 |
10 | 33145445093 |
11 | 13069815532 |
12 | 6510413a05 |
13 | 3182c42207 |
14 | 18660b1ba5 |
15 | cded4c948 |
hex | 7b79f5ae5 |
33145445093 has 2 divisors, whose sum is σ = 33145445094. Its totient is φ = 33145445092.
The previous prime is 33145445087. The next prime is 33145445101. The reversal of 33145445093 is 39054454133.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23932708804 + 9212736289 = 154702^2 + 95983^2 .
It is a cyclic number.
It is not a de Polignac number, because 33145445093 - 24 = 33145445077 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 33145445093.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33145445063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16572722546 + 16572722547.
It is an arithmetic number, because the mean of its divisors is an integer number (16572722547).
Almost surely, 233145445093 is an apocalyptic number.
It is an amenable number.
33145445093 is a deficient number, since it is larger than the sum of its proper divisors (1).
33145445093 is an equidigital number, since it uses as much as digits as its factorization.
33145445093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 33145445093 in words is "thirty-three billion, one hundred forty-five million, four hundred forty-five thousand, ninety-three".
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