Base | Representation |
---|---|
bin | 11110110111110111… |
… | …111000010001101111 |
3 | 10011120020220200221222 |
4 | 132313313320101233 |
5 | 1020342302300111 |
6 | 23121224013555 |
7 | 2252323243001 |
oct | 366767702157 |
9 | 104506820858 |
10 | 33149650031 |
11 | 13071127793 |
12 | 65119012bb |
13 | 3183a85144 |
14 | 1866888371 |
15 | ce03cd7db |
hex | 7b7df846f |
33149650031 has 2 divisors, whose sum is σ = 33149650032. Its totient is φ = 33149650030.
The previous prime is 33149650003. The next prime is 33149650043. The reversal of 33149650031 is 13005694133.
It is a strong prime.
It is an emirp because it is prime and its reverse (13005694133) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 33149650031 - 234 = 15969780847 is a prime.
It is a super-2 number, since 2×331496500312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 33149649973 and 33149650000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33149650931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16574825015 + 16574825016.
It is an arithmetic number, because the mean of its divisors is an integer number (16574825016).
Almost surely, 233149650031 is an apocalyptic number.
33149650031 is a deficient number, since it is larger than the sum of its proper divisors (1).
33149650031 is an equidigital number, since it uses as much as digits as its factorization.
33149650031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 35.
The spelling of 33149650031 in words is "thirty-three billion, one hundred forty-nine million, six hundred fifty thousand, thirty-one".
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