Base | Representation |
---|---|
bin | 10011110000101… |
… | …100010000100100 |
3 | 212002211112110001 |
4 | 103300230100210 |
5 | 1134333000200 |
6 | 52521511044 |
7 | 11133653362 |
oct | 2360542044 |
9 | 762745401 |
10 | 331531300 |
11 | 160160411 |
12 | 93042484 |
13 | 538baa89 |
14 | 32060632 |
15 | 1e18b76a |
hex | 13c2c424 |
331531300 has 36 divisors (see below), whose sum is σ = 723117780. Its totient is φ = 131931520.
The previous prime is 331531259. The next prime is 331531303. The reversal of 331531300 is 3135133.
It can be written as a sum of positive squares in 6 ways, for example, as 6666724 + 324864576 = 2582^2 + 18024^2 .
It is not an unprimeable number, because it can be changed into a prime (331531303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11286 + ... + 28114.
It is an arithmetic number, because the mean of its divisors is an integer number (20086605).
Almost surely, 2331531300 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 331531300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (361558890).
331531300 is an abundant number, since it is smaller than the sum of its proper divisors (391586480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
331531300 is a wasteful number, since it uses less digits than its factorization.
331531300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17040 (or 17033 counting only the distinct ones).
The product of its (nonzero) digits is 405, while the sum is 19.
The square root of 331531300 is about 18208.0009885764. Note that the first 3 decimals coincide. The cubic root of 331531300 is about 692.1095558666.
Adding to 331531300 its reverse (3135133), we get a palindrome (334666433).
It can be divided in two parts, 33153 and 1300, that added together give a triangular number (34453 = T262).
The spelling of 331531300 in words is "three hundred thirty-one million, five hundred thirty-one thousand, three hundred".
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