Base | Representation |
---|---|
bin | 11110111010111100… |
… | …100110110111111001 |
3 | 10011200211221210012001 |
4 | 132322330212313321 |
5 | 1020444003033423 |
6 | 23130305221001 |
7 | 2253520503004 |
oct | 367274466771 |
9 | 104624853161 |
10 | 33201221113 |
11 | 13098250915 |
12 | 6527031761 |
13 | 3191670688 |
14 | 186d67053b |
15 | ce4bb8cad |
hex | 7baf26df9 |
33201221113 has 2 divisors, whose sum is σ = 33201221114. Its totient is φ = 33201221112.
The previous prime is 33201221111. The next prime is 33201221197. The reversal of 33201221113 is 31112210233.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29119033449 + 4082187664 = 170643^2 + 63892^2 .
It is a cyclic number.
It is not a de Polignac number, because 33201221113 - 21 = 33201221111 is a prime.
It is a super-2 number, since 2×332012211132 (a number of 22 digits) contains 22 as substring.
Together with 33201221111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (33201221111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16600610556 + 16600610557.
It is an arithmetic number, because the mean of its divisors is an integer number (16600610557).
Almost surely, 233201221113 is an apocalyptic number.
It is an amenable number.
33201221113 is a deficient number, since it is larger than the sum of its proper divisors (1).
33201221113 is an equidigital number, since it uses as much as digits as its factorization.
33201221113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 33201221113 its reverse (31112210233), we get a palindrome (64313431346).
The spelling of 33201221113 in words is "thirty-three billion, two hundred one million, two hundred twenty-one thousand, one hundred thirteen".
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