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332013135215543 is a prime number
BaseRepresentation
bin100101101111101101101010…
…0111111000011101110110111
31121112120010221020201021121212
41023133123110333003232313
5322004200400103344133
63134044421221432035
7126635105000154365
oct11337332477035667
91545503836637555
10332013135215543
1196875a862a01a1
12312a245326b61b
13113349204a0802
145bdb742d58635
15285b654876148
hex12df6d4fc3bb7

332013135215543 has 2 divisors, whose sum is σ = 332013135215544. Its totient is φ = 332013135215542.

The previous prime is 332013135215491. The next prime is 332013135215551. The reversal of 332013135215543 is 345512531310233.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 332013135215543 - 216 = 332013135150007 is a prime.

It is a super-2 number, since 2×3320131352155432 (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 332013135215543.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (332013135212543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166006567607771 + 166006567607772.

It is an arithmetic number, because the mean of its divisors is an integer number (166006567607772).

Almost surely, 2332013135215543 is an apocalyptic number.

332013135215543 is a deficient number, since it is larger than the sum of its proper divisors (1).

332013135215543 is an equidigital number, since it uses as much as digits as its factorization.

332013135215543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486000, while the sum is 41.

Adding to 332013135215543 its reverse (345512531310233), we get a palindrome (677525666525776).

The spelling of 332013135215543 in words is "three hundred thirty-two trillion, thirteen billion, one hundred thirty-five million, two hundred fifteen thousand, five hundred forty-three".