Base | Representation |
---|---|
bin | 1111000110100100100010… |
… | …00000101101000001100011 |
3 | 11100120221201001111221010012 |
4 | 13203102101000231001203 |
5 | 13323112333210412121 |
6 | 154344551121155135 |
7 | 6665265341221424 |
oct | 743222100550143 |
9 | 140527631457105 |
10 | 33211120013411 |
11 | a64483648765a |
12 | 3884654a8baab |
13 | 156ba450159c2 |
14 | 82b5d915564b |
15 | 3c8d6dd3ac5b |
hex | 1e349102d063 |
33211120013411 has 2 divisors, whose sum is σ = 33211120013412. Its totient is φ = 33211120013410.
The previous prime is 33211120013381. The next prime is 33211120013413. The reversal of 33211120013411 is 11431002111233.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33211120013411 is a prime.
It is a super-2 number, since 2×332111200134112 (a number of 28 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 33211120013413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (33211120013413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16605560006705 + 16605560006706.
It is an arithmetic number, because the mean of its divisors is an integer number (16605560006706).
Almost surely, 233211120013411 is an apocalyptic number.
33211120013411 is a deficient number, since it is larger than the sum of its proper divisors (1).
33211120013411 is an equidigital number, since it uses as much as digits as its factorization.
33211120013411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 33211120013411 its reverse (11431002111233), we get a palindrome (44642122124644).
The spelling of 33211120013411 in words is "thirty-three trillion, two hundred eleven billion, one hundred twenty million, thirteen thousand, four hundred eleven".
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