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3321402122113 is a prime number
BaseRepresentation
bin110000010101010010111…
…111100101111110000001
3102202112010020001202101121
4300111102333211332001
5413404212420401423
611021455302232241
7461651304135055
oct60252277457601
912675106052347
103321402122113
111070664a000a9
12457862a25681
131b128c678a9a
14b6a84625c65
155b5e5cd245d
hex30552fe5f81

3321402122113 has 2 divisors, whose sum is σ = 3321402122114. Its totient is φ = 3321402122112.

The previous prime is 3321402122107. The next prime is 3321402122161. The reversal of 3321402122113 is 3112212041233.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3124010295169 + 197391826944 = 1767487^2 + 444288^2 .

It is a cyclic number.

It is not a de Polignac number, because 3321402122113 - 241 = 1122378866561 is a prime.

It is a super-2 number, since 2×33214021221132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3321402122813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1660701061056 + 1660701061057.

It is an arithmetic number, because the mean of its divisors is an integer number (1660701061057).

Almost surely, 23321402122113 is an apocalyptic number.

It is an amenable number.

3321402122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3321402122113 is an equidigital number, since it uses as much as digits as its factorization.

3321402122113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 3321402122113 its reverse (3112212041233), we get a palindrome (6433614163346).

The spelling of 3321402122113 in words is "three trillion, three hundred twenty-one billion, four hundred two million, one hundred twenty-two thousand, one hundred thirteen".