Base | Representation |
---|---|
bin | 110000010110001001010… |
… | …110111100110000101001 |
3 | 102202121110210022211211221 |
4 | 300112021112330300221 |
5 | 413413044414330231 |
6 | 11022130003422041 |
7 | 462013020606265 |
oct | 60261126746051 |
9 | 12677423284757 |
10 | 3322314214441 |
11 | 1070a92841612 |
12 | 457a78384921 |
13 | 1b13a66174a1 |
14 | b6b2d80d0a5 |
15 | 5b64adebd11 |
hex | 305895bcc29 |
3322314214441 has 2 divisors, whose sum is σ = 3322314214442. Its totient is φ = 3322314214440.
The previous prime is 3322314214433. The next prime is 3322314214543. The reversal of 3322314214441 is 1444124132233.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3150284209216 + 172030005225 = 1774904^2 + 414765^2 .
It is an emirp because it is prime and its reverse (1444124132233) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3322314214441 - 23 = 3322314214433 is a prime.
It is a super-2 number, since 2×33223142144412 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3322314214397 and 3322314214406.
It is not a weakly prime, because it can be changed into another prime (3322314211441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1661157107220 + 1661157107221.
It is an arithmetic number, because the mean of its divisors is an integer number (1661157107221).
Almost surely, 23322314214441 is an apocalyptic number.
It is an amenable number.
3322314214441 is a deficient number, since it is larger than the sum of its proper divisors (1).
3322314214441 is an equidigital number, since it uses as much as digits as its factorization.
3322314214441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 55296, while the sum is 34.
Adding to 3322314214441 its reverse (1444124132233), we get a palindrome (4766438346674).
The spelling of 3322314214441 in words is "three trillion, three hundred twenty-two billion, three hundred fourteen million, two hundred fourteen thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.171 sec. • engine limits •