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332312120300099 is a prime number
BaseRepresentation
bin100101110001111000111000…
…1111000101001001001000011
31121120121201200000220021010002
41023203301301320221021003
5322024100210244100344
63134434025221430215
7126665521062354632
oct11343616170511103
91546551600807102
10332312120300099
11969808626064a5
123133039486b36b
1311356b8ac6c224
145c0bdc7389519
152864302da944e
hex12e3c71e29243

332312120300099 has 2 divisors, whose sum is σ = 332312120300100. Its totient is φ = 332312120300098.

The previous prime is 332312120300081. The next prime is 332312120300191. The reversal of 332312120300099 is 990003021213233.

It is a weak prime.

It is an emirp because it is prime and its reverse (990003021213233) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-332312120300099 is a prime.

It is a super-2 number, since 2×3323121203000992 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (332312120350099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166156060150049 + 166156060150050.

It is an arithmetic number, because the mean of its divisors is an integer number (166156060150050).

Almost surely, 2332312120300099 is an apocalyptic number.

332312120300099 is a deficient number, since it is larger than the sum of its proper divisors (1).

332312120300099 is an equidigital number, since it uses as much as digits as its factorization.

332312120300099 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 52488, while the sum is 38.

The spelling of 332312120300099 in words is "three hundred thirty-two trillion, three hundred twelve billion, one hundred twenty million, three hundred thousand, ninety-nine".