Base | Representation |
---|---|
bin | 100101110001111100100111… |
… | …1011111011110011111000111 |
3 | 1121120122111100110121100221202 |
4 | 1023203321033133132133013 |
5 | 322024213113100241403 |
6 | 3134441432302133115 |
7 | 126666223461113261 |
oct | 11343711737363707 |
9 | 1546574313540852 |
10 | 332320133212103 |
11 | 969841a46a2923 |
12 | 31331a5028119b |
13 | 1135786708348a |
14 | 5c0c547654b31 |
15 | 28646215a5688 |
hex | 12e3e4f7de7c7 |
332320133212103 has 2 divisors, whose sum is σ = 332320133212104. Its totient is φ = 332320133212102.
The previous prime is 332320133212099. The next prime is 332320133212229. The reversal of 332320133212103 is 301212331023233.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 332320133212103 - 22 = 332320133212099 is a prime.
It is a super-2 number, since 2×3323201332121032 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (332320133212003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166160066606051 + 166160066606052.
It is an arithmetic number, because the mean of its divisors is an integer number (166160066606052).
Almost surely, 2332320133212103 is an apocalyptic number.
332320133212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
332320133212103 is an equidigital number, since it uses as much as digits as its factorization.
332320133212103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 29.
Adding to 332320133212103 its reverse (301212331023233), we get a palindrome (633532464235336).
The spelling of 332320133212103 in words is "three hundred thirty-two trillion, three hundred twenty billion, one hundred thirty-three million, two hundred twelve thousand, one hundred three".
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