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33240312240131 is a prime number
BaseRepresentation
bin1111000111011010111010…
…00000001101100000000011
311100200202001111211200212102
413203231131000031200003
513324102124413141011
6154410215540021015
710000350632110223
oct743553500154003
9140622044750772
1033240312240131
11a656156760667
12388a24139176b
131571717c35a39
1482cba81b0083
153c99cbaa473b
hex1e3b5d00d803

33240312240131 has 2 divisors, whose sum is σ = 33240312240132. Its totient is φ = 33240312240130.

The previous prime is 33240312240101. The next prime is 33240312240133. The reversal of 33240312240131 is 13104221304233.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 33240312240131 - 222 = 33240308045827 is a prime.

It is a super-2 number, since 2×332403122401312 (a number of 28 digits) contains 22 as substring.

Together with 33240312240133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 33240312240094 and 33240312240103.

It is not a weakly prime, because it can be changed into another prime (33240312240133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16620156120065 + 16620156120066.

It is an arithmetic number, because the mean of its divisors is an integer number (16620156120066).

Almost surely, 233240312240131 is an apocalyptic number.

33240312240131 is a deficient number, since it is larger than the sum of its proper divisors (1).

33240312240131 is an equidigital number, since it uses as much as digits as its factorization.

33240312240131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 33240312240131 its reverse (13104221304233), we get a palindrome (46344533544364).

The spelling of 33240312240131 in words is "thirty-three trillion, two hundred forty billion, three hundred twelve million, two hundred forty thousand, one hundred thirty-one".