33240401323 has 2 divisors, whose sum is σ = 33240401324. Its totient is φ = 33240401322.

The previous prime is 33240401281. The next prime is 33240401353. The reversal of 33240401323 is 32310404233.

It is a strong prime.

It is an emirp because it is prime and its reverse (32310404233) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33240401323 is a prime.

It is a super-2 number, since 2×33240401323² (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (33240401353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16620200661 + 16620200662.

It is an arithmetic number, because the mean of its divisors is an integer number (16620200662).

Almost surely, 2^33240401323 is an apocalyptic number.

33240401323 is a deficient number, since it is larger than the sum of its proper divisors (1).

33240401323 is an equidigital number, since it uses as much as digits as its factorization.

33240401323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 33240401323 its reverse (32310404233), we get a palindrome (65550805556).

The spelling of 33240401323 in words is "thirty-three billion, two hundred forty million, four hundred one thousand, three hundred twenty-three".