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332440241293 is a prime number
BaseRepresentation
bin1001101011001101111…
…10111000010010001101
31011210002022222000212101
410311212332320102031
520421314200210133
6412415420035101
733006115266316
oct4654676702215
91153068860771
10332440241293
11118a94938776
1254519692a91
132546c92bc64
14121396c360d
1589aa65c37d
hex4d66fb848d

332440241293 has 2 divisors, whose sum is σ = 332440241294. Its totient is φ = 332440241292.

The previous prime is 332440241239. The next prime is 332440241297. The reversal of 332440241293 is 392142044233.

Together with previous prime (332440241239) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 233943440329 + 98496800964 = 483677^2 + 313842^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-332440241293 is a prime.

It is a super-2 number, since 2×3324402412932 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (332440241297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 166220120646 + 166220120647.

It is an arithmetic number, because the mean of its divisors is an integer number (166220120647).

Almost surely, 2332440241293 is an apocalyptic number.

It is an amenable number.

332440241293 is a deficient number, since it is larger than the sum of its proper divisors (1).

332440241293 is an equidigital number, since it uses as much as digits as its factorization.

332440241293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 37.

The spelling of 332440241293 in words is "three hundred thirty-two billion, four hundred forty million, two hundred forty-one thousand, two hundred ninety-three".