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3325134212201 is a prime number
BaseRepresentation
bin110000011000110001011…
…100011000110001101001
3102202212202022122120112102
4300120301130120301221
5413434333324242301
611023313502023145
7462142632314144
oct60306134306151
912685668576472
103325134212201
1110721aa63867a
12458524877ab5
131b1735926b09
14b6d1a15b05b
155b763786b6b
hex30631718c69

3325134212201 has 2 divisors, whose sum is σ = 3325134212202. Its totient is φ = 3325134212200.

The previous prime is 3325134212131. The next prime is 3325134212203. The reversal of 3325134212201 is 1022124315233.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3011349384976 + 313784827225 = 1735324^2 + 560165^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3325134212201 is a prime.

It is a super-2 number, since 2×33251342122012 (a number of 26 digits) contains 22 as substring.

Together with 3325134212203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3325134212203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1662567106100 + 1662567106101.

It is an arithmetic number, because the mean of its divisors is an integer number (1662567106101).

Almost surely, 23325134212201 is an apocalyptic number.

It is an amenable number.

3325134212201 is a deficient number, since it is larger than the sum of its proper divisors (1).

3325134212201 is an equidigital number, since it uses as much as digits as its factorization.

3325134212201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 3325134212201 its reverse (1022124315233), we get a palindrome (4347258527434).

The spelling of 3325134212201 in words is "three trillion, three hundred twenty-five billion, one hundred thirty-four million, two hundred twelve thousand, two hundred one".