Base | Representation |
---|---|
bin | 110000011101010100001… |
… | …011101010111101010011 |
3 | 102210100100021001212120212 |
4 | 300131110023222331103 |
5 | 414024331033000313 |
6 | 11025441505554335 |
7 | 462404541655106 |
oct | 60352413527523 |
9 | 12710307055525 |
10 | 3330012000083 |
11 | 1074282a6292a |
12 | 4594663459ab |
13 | 1b2032365932 |
14 | b725dcc873d |
15 | 5b94baec3a8 |
hex | 307542eaf53 |
3330012000083 has 2 divisors, whose sum is σ = 3330012000084. Its totient is φ = 3330012000082.
The previous prime is 3330012000031. The next prime is 3330012000103. The reversal of 3330012000083 is 3800002100333.
It is a strong prime.
It is an emirp because it is prime and its reverse (3800002100333) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3330012000083 - 212 = 3330011995987 is a prime.
It is a super-2 number, since 2×33300120000832 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (3330012000013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665006000041 + 1665006000042.
It is an arithmetic number, because the mean of its divisors is an integer number (1665006000042).
Almost surely, 23330012000083 is an apocalyptic number.
3330012000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
3330012000083 is an equidigital number, since it uses as much as digits as its factorization.
3330012000083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
The spelling of 3330012000083 in words is "three trillion, three hundred thirty billion, twelve million, eighty-three", and thus it is an aban number.
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