Base | Representation |
---|---|
bin | 110000011101010100001… |
… | …011101010111101100111 |
3 | 102210100100021001212121121 |
4 | 300131110023222331213 |
5 | 414024331033000403 |
6 | 11025441505554411 |
7 | 462404541655135 |
oct | 60352413527547 |
9 | 12710307055547 |
10 | 3330012000103 |
11 | 1074282a62948 |
12 | 459466345a07 |
13 | 1b2032365949 |
14 | b725dcc8755 |
15 | 5b94baec3bd |
hex | 307542eaf67 |
3330012000103 has 2 divisors, whose sum is σ = 3330012000104. Its totient is φ = 3330012000102.
The previous prime is 3330012000083. The next prime is 3330012000131. The reversal of 3330012000103 is 3010002100333.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3330012000103 - 217 = 3330011869031 is a prime.
It is a super-2 number, since 2×33300120001032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3330012000193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1665006000051 + 1665006000052.
It is an arithmetic number, because the mean of its divisors is an integer number (1665006000052).
Almost surely, 23330012000103 is an apocalyptic number.
3330012000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
3330012000103 is an equidigital number, since it uses as much as digits as its factorization.
3330012000103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 16.
Adding to 3330012000103 its reverse (3010002100333), we get a palindrome (6340014100436).
The spelling of 3330012000103 in words is "three trillion, three hundred thirty billion, twelve million, one hundred three", and thus it is an aban number.
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