Base | Representation |
---|---|
bin | 11111000001000110… |
… | …010110110011111101 |
3 | 10011222001011211222001 |
4 | 133001012112303331 |
5 | 1021201414040221 |
6 | 23144433422301 |
7 | 2256213032614 |
oct | 370106266375 |
9 | 104861154861 |
10 | 33304440061 |
11 | 13140540832 |
12 | 655570a991 |
13 | 31a9b70389 |
14 | 187d25c87b |
15 | cedca7391 |
hex | 7c1196cfd |
33304440061 has 2 divisors, whose sum is σ = 33304440062. Its totient is φ = 33304440060.
The previous prime is 33304440007. The next prime is 33304440079. The reversal of 33304440061 is 16004440333.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24839336025 + 8465104036 = 157605^2 + 92006^2 .
It is a cyclic number.
It is not a de Polignac number, because 33304440061 - 213 = 33304431869 is a prime.
It is a super-2 number, since 2×333044400612 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (33304440761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16652220030 + 16652220031.
It is an arithmetic number, because the mean of its divisors is an integer number (16652220031).
Almost surely, 233304440061 is an apocalyptic number.
It is an amenable number.
33304440061 is a deficient number, since it is larger than the sum of its proper divisors (1).
33304440061 is an equidigital number, since it uses as much as digits as its factorization.
33304440061 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 33304440061 its reverse (16004440333), we get a palindrome (49308880394).
The spelling of 33304440061 in words is "thirty-three billion, three hundred four million, four hundred forty thousand, sixty-one".
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